How do you simplify #7sqrtx+3sqrty-sqrtx-3sqrty#?

Question

1959 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-16T05:58:08

#6\sqrt{x}#

The #3\sqrt{y}-3\sqrt{y}# cancel each other out.

This leaves you: #7\sqrt{x}-\sqrt{x}#

Since they have the same variables, they can be treated as normal algebra, which gives you #6\sqrt{x}#

Answer 2 · 2018-05-16T05:59:11

#6sqrtx#

Add the like terms first and then simplify further.

#7sqrtx + 3sqrty - sqrtx - 3sqrty#

#7sqrtx-sqrtx+3sqrty-3sqrty#

#7sqrtx-sqrtx+cancel(3sqrty-3sqrty)#

#7sqrtx-sqrtx#

#6sqrtx#

Another way to arrive to #6sqrtx# is:

#7sqrtx-sqrtx#

#sqrtx(7 - 1)#

#sqrtx xx 6#

#6sqrtx#