How do you solve for x: in #x - 8 + x = 1 - 4x #? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Sebby · Stefan V. May 16, 2018 #x = 3/2# Explanation: #x - 8 + x = 1 - 4x# #x - 9 + x = -4x# #x - 9 = -5x# #6x = 9# #x = 9/6# #x = 3/2# Opposite operation on like terms on either side to bring all #x# terms and integer terms onto opposite sides of the equals. Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1650 views around the world You can reuse this answer Creative Commons License