Number problem?

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2 Answers
May 16, 2018

See below

Explanation:

"There are two numbers.."

One is #x#. The other is 7 more than twice the first, then #x# and #7+2x# are both numbers

The sum is 43, then #x+7+2x=43# is the equation to solve

Group similar terms and transposing terms #2x+x=43-7#

#3x=36#

#x=36/3=12#

One number is #12#. The other is #2·12+7=31#

May 16, 2018

Equation: #x+(2x+7)=43# Numbers: #12, 31#

Explanation:

Assuming that #x# is the smaller number, we know that the larger number equals #7# more than twice the smaller number. This is equivalent to saying the larger number = #2x+7#

The second thing we are told is that the sum of the two numbers is equivalent to #43#. The smaller number equals #x#, and the larger number equals #2x+7#. Therefore their sum is equal to #43# but also #x+2x+7#. So #43=x+2x+7#.
#43=3x+7#
#36=3x#
#12=x#

Since we know the larger number is #2x+7#, and #x=12#, then the larger number is equal to #2(12)+7=31#.

Therefore the two numbers in ascending order are #12# and #31#.