Given sinx=45 and cosx=35 . What is ratio for tanx ?

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Answer 1 · 2018-05-17T19:06:37

$tan x = \frac{9}{7}$ $tanx=9/7$

$tan x$ $tanx$ is defined as $\frac{sin x}{cos x}$ $sinx/cosx$ . Since we know both of these values, we can plug in and get

$tan x = \frac{45}{35}$ $tanx=45/35$

Both terms can be simplified by dividing by $5$ $5$ . We get

$tan x = \frac{9}{7}$ $tanx=9/7$

Hope this helps!

Answer 2 · 2018-05-17T22:36:30

Impossible.

sin x should always be --> - 1< sin x < 1
cos x should always be --> - 1< cos x < 1
Therefor, the question is impossible.

Given sinx=45 and cosx=35 . What is ratio for ​ tanx ​ ?