If $g (x) = 9 x^{2} + 3 x$ $g(x) = 9x^2+3x$ how do you find $g (- 3)$ $g(-3)$ ?

Question

3639 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-18T04:14:31

$= 72$ $= 72$

We have to put $- 3$ $-3$ in place of $x$ $x$ . Given

$g (x) = 9 x^{2} + 3 x$ $g(x)= 9x^2 +3x$

Putting $g = - 3$ $g = -3$

$g (- 3) = 9 {(- 3)}^{2} + 3 (- 3)$ $g(-3) = 9(-3)^2 + 3(-3)$

$= 81 - 9$ $= 81 -9$

$= 72$ $= 72$

If g(x)=9x2+3xg(x) = 9x^2+3x how do you find g(−3)g(-3)?