Can someone please help with this **logarithms** question?
1 Answer
May 18, 2018
Use properties of logarithms for all of the following.
i)
logp√x=logpx12=12logpx=92 ii)
logp(1x)=logp1−logpx=0−9=−9 iii)
logp(xy)=logpx+logpy=9+6=15 iv)
logyx=logxlogy=logpxlogpy=96=32
Hopefully this helps!