What is the slope and x intercept of the line $3 x - 2 y = 12$ $3x - 2y = 12$ ?

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Answer 1 · 2018-05-19T22:23:50

Need to format the equation in $y = m x + b$ $y=mx + b$ .

$3 x - 2 y = 12$ $3x−2y = 12$

$3 x - 12 = 2 y$ $3x -12 = 2y$

$y = \frac{3}{2} x - \frac{12}{2}$ $y = 3/2x -12/2$

$y = \frac{3}{2} x - 6$ $y = 3/2x -6$

The slope is $\frac{3}{2}$ $3/2$ or $1 \frac{1}{2}$ $1 1/2$ . The $x$ $x$ -intercept is at $y = 0$ $y = 0$ , hence

$2 y = 3 x - 12$ $2y = 3x -12$

$2 (0) = 3 x - 12$ $2(0) = 3x -12$

$0 = 3 x - 12$ $0 = 3x - 12" "$ (isolate $x$ $x$ for the intercept)

$12 = 3 x$ $12 = 3x$

$\frac{12}{3} = \frac{3 x}{3}$ $12/3 = (3x)/3$

$4 = x$ $4 = x$

The intercepts are

What is the slope and x intercept of the line 3x−2y=123x - 2y = 12?