Question

How do you evaluate `log_7 (1/49)`?

Answer 1

`log_7(1/49)=x`

`7^x=(1/49)`

Explanation:

Answer 2

Ans -2

Explanation:

`log_7 (1/49)` = y

`log_7 (1/(7^2))` =y

`log_7 (7^-2)` =y

y = -2