How do you evaluate the expression $2^{{log}_{2} 45}$ $2^(log_2 45)$ ?

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Answer 1 · 2018-05-20T01:54:32

$45$ $45$

exponentiation and log are inverse functions
$a^{{log}_{a} (b)} = b$ $a^(log_a(b))=b$
$cancela^(cancellog_a(b))$
$b=45$

How do you evaluate the expression 2^(log_2 45)2log2452^(log_2 45)?