What is the slope of any line perpendicular to the line passing through $(- 9, 8)$ $(-9,8)$ and $(- 1, 1)$ $(-1,1)$ ?

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Answer 1 · 2018-05-20T15:17:47

$m'=8/7$

First find the slope of this line:

$m=(y_2 - y_1)/(x_2-x_1)$

$m=(1 - 8)/(-1-(-9))$

$m=-7/8$

formula for a perpendicular slope is $m'=-1/m$

$m'=-1/(-7/8) = 8/7$

Answer 2 · 2018-05-20T15:22:32

$8/7$

find the slope of the two given points
from the two points slope formula:

$m = (y_2-y_1)/(x_2-x_1)$

$(-9,8) " and " (-1,1)$

$x_1=-9$

$x_2=-1$

$y_1=8$

$y_2=1$

$m = (1-8)/(-1-(-9)) = -7/8$

perpendicular slope means the reciprocal in the opposite sign

so $8/7$

What is the slope of any line perpendicular to the line passing through (-9,8)(−9,8)(-9,8) and (-1,1)(−1,1)(-1,1)?