Question

How do you evaluate `sin(tan^-1(sqrt3))`?

Answer 1

`\frac{\sqrt{3}}{2}` , `\frac{-\sqrt{3}}{2}`

Explanation:

Diagram Of Right Triangle
As you can see from the diagram, `\theta = \frac{\pi}{3} and \frac{4\pi}{3}` radians or 60° and 240°

Using the tangent law and sine law of right triangles, you will find that `\sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2} and \sin(\frac{4\pi}{3}) = -\frac{\sqrt{3}}{2}`