How do you solve? y=ln(x^2+1)

Is derived y=ln(x^2+1)

1 Answer
May 22, 2018

Please see the explanation.

Explanation:

#y=ln(x^2+1)#

Solving a function means to find the roots or zeros of the function. On the graph of a function the solution(s) is the point(s) where the curve touches or crosses the x-axis AKA the x-intercept(s). To find the x-intercepts of a function we need to set y to zero and solve for x, therefore in this case we have:

#ln(x^2+1)=0#
#x^2+1=e^0=1#
#x^2=0#
#x=0#

Notice the graph in the link below, the graph touches the x-axis at only one point i.e: (0, 0).

https://www.desmos.com/calculator/yyley7aguo