How do you solve x2+14x+49=19?

1 Answer
Roy Ø.
May 22, 2018

x2+14x+49=19 has the two solutions x=−7±√19
(i.e. x1=−7−√19 and x2=−7+√19)

Explanation:

The first I notice is that 14=2⋅7, and 49=72

Please also remember that (x+a)2=x2+2a+a2
Therefore x2+14x+49=(x+7)2=19

It follows, therefore, that
x+7=±√19

We, therefore, have two values of x here:
x=−7±√19

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