Question

The average nicotine (C10H14N2, molar mass 162.3 g/mol) content of a Camel cigarette is 1.93 mg. Suppose an individual smokes one pack of 20 cigarettes a day. How many moles of nicotine are smoked in a day?

Answer 1

`2.38*10^-4` moles of nicotine.

Explanation:

First, we need to solve for how many milligrams of nicotine is in one pack of cigarettes. All we need to do is times the average amount of nicotine in one cigarette by how many cigarettes are in a pack.

`1.93mg * 20 = 38.6 mg`

Now we need to convert milligrams into grams. There are 1000 mg per 1 g of any substance. Using this ratio we can solve for grams.

`38.6mg((1 g)/(1000mg))=0.0386 g`

Next, we use the molar mass which has been given to us in the original problem. The molar mass tells us how many grams are in one mole of that particular substance. Using this we can convert our grams of nicotine into moles of nicotine.

`0.0386g((1mol)/(162.3g))=2.38*10^-4mol`