Find all angles a in the interval [0degrees, 360 degrees] such that sin^2a-sina =0?

1 Answer
Nghi N
May 23, 2018

#0, 90^@, 180^@, 360^@#

Explanation:

#sin^2 a - sin a = 0#
sin a(sin a - 1) = 0
Either factor should be zero -->
a. sin a = 0
Unit circle gives:
a = 0, #a = 180^@#, and #a = 360^@#
b. sin a - 1 = 0 --> sin a = 1
#a = 90^2#

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