What is the factored form of #x^2-8x+12#?

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Answer 1 · 2018-05-23T18:44:32

#(x-6)(x-2)#

#x^2-8x+12#

Find numbers a and b such that:

#a +b=-8#
#a*b=12#

#a=-2#
#b=-6#

#x^2-8x+12#

#(x-6)(x-2)#

graph{x^2-8x+12 [-10, 10, -5, 5]}