What volume of 0.250 mol/L (aq) solution contains 12.8g of Na2CO3? (I dont know how to use the gas laws, the answer is 483 mL, but I dont know how to get that)

1 Answer
Al E.
May 23, 2018

Firstly, this has nothing to do with gas laws!

This is asking us to perform a stoichiometric calculation by relating data presented and molecular weights.

Hence,

#12.8"g" * (Na_2CO_3)/(106"g") * "L"/(0.250"mol") approx 483"mL"#

of #0.250"M"# #Na_2CO_3# have that mass of sodium carbonate dissolved.

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