Question

How do you evaluate the definite integral `int (-3v+4)dv` from [2,5]?

Answer 1

`-39/2`

Explanation:

`int_2^5(-3v+4)dv`

the antiderivative is `F(v)=-3/2v^2+4v`

simply evaluate `F(5)-F(2)`
`=-3/2(5)^2+4(5)+3/2(2)^2-4(2)`
`=-75/2+20+6-8`
`=-39/2`