How do you solve ${ln x}^{2} = 9$ $lnx^2=9$ ?

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How do you solve ${ln x}^{2} = 9$ $lnx^2=9$ ?

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Answer 1 · 2018-05-24T02:51:14

$e^{\frac{9}{2}}$ $e^ {frac{9}{2}}$

Explanation:

Take e to the power of both sides:
$e^{ln (x^{2})} = e^{9}$ $e^ln(x^2) = e^9$
$x^{2} = e^{9}$ $x^2 = e^9$
$x = \pm \sqrt{e^{9}} \approx \pm 90.0171313$ $x = \pm \sqrt{e^9} \approx \pm 90.0171313$

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How do you solve ${ln x}^{2} = 9$ $lnx^2=9$ ?

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