The length of the square plot in which roses are planted is 2 meters greater than the length of the square plot in which marigolds are planted. How much bigger in area is the rose plot than the marigold plot?

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The length of the square plot in which roses are planted is 2 meters greater than the length of the square plot in which marigolds are planted. How much bigger in area is the rose plot than the marigold plot?

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Answer 1 · 2018-05-24T07:13:26

4 times the length of the marigold plot plus 4

Explanation:

Let $x$ $x$ = length of the marigold plot.
So, the area of the marigold plot is $A_{m} = x^{2}$ $A_m= x^2$ .
The length of the rose plot is 2 meters more than the marigold plot, that is, $x + 2$ $x+2$ . So, the area of the rose plot is $A_{r} = {(x + 2)}^{2}$ $A_r = (x+2)^2$

The difference between the plots is $A_{r} - A_{m}$ $A_r - A_m$ :
$= {(x + 2)}^{2} - x^{2}$ $= (x+2)^2 - x^2$
$= x^{2} + 4 x + 4 - x^{2}$ $= x^2 + 4x + 4 - x^2$
$= 4 x + 4$ $= 4x + 4$

So the answer is variable, and depends on the length of the marigold plot.

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The length of the square plot in which roses are planted is 2 meters greater than the length of the square plot in which marigolds are planted. How much bigger in area is the rose plot than the marigold plot?

1 Answer

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