How do you find the x and y intercepts for 2x + 4y = -82x+4y=−8?

2 Answers
Daniel L.
May 24, 2018

See explanation.

Explanation:

To find xx interxept of a function you have to substitute 00 for yy and solve the equation for xx:

2*x+4*0=-82⋅x+4⋅0=−8

2x=-82x=−8

x=-4x=−4

The xx intercept is the point (-4,0)(−4,0).

To find yy intercept you have to substitute 00 for xx and solve the equation for yy:

2*0+4*y=-82⋅0+4⋅y=−8

4y=-84y=−8

y=-2y=−2

The yy intercept is the point (0,-2)(0,−2).

Bhavin B.
May 24, 2018

x-intercept = (-4,0)(−4,0)
y-intercept = (0,-2(0,−2)

Explanation:

x-intercept is when y=0y=0
y-intercept is when x=0x=0

Step 1:
Lets find the x-intercept by putting y=0y=0

2x+4y=-82x+4y=−8

2x +(4 xx 0) = -82x+(4×0)=−8

2x +0 = -82x+0=−8

2x=-82x=−8

x= -8/2x=−82

x = -4x=−4 ------> x-intercept is (-4,0)(−4,0)

Step 2:
Lets find the y-intercept by putting x=0x=0

2x+4y=-82x+4y=−8

#(2 xx 0) +4y = -8

0 + 4y = -80+4y=−8

4y=-84y=−8

y=-8/4y=−84

y = -2y=−2 -----> y-intercept is (0,-2)(0,−2)

if we plot the graph, we get the same. enter image source here

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