Find the Taylor series expansion formula of #f(x)=\lnx# at #a=3#?
#f'=1/x=x^-1#
#f''=-1/x^2=(-1)x^-2#
#f'''=2/x^3=(-1)(-2)x^-3#
#f^4=(-1)(-2)(-3)x^-4...#
must find #C_n# before finding #f(x)# expansion
must find
1 Answer
May 24, 2018
Explanation:
In general, for
We also have