How do you find the derivative of y = ln(1-(x^2))y=ln(1(x2))?

1 Answer
May 24, 2018

Recall that d/dxln(x)=1/xddxln(x)=1x.

So, by the chain rule, when we put a function inside the natural log function, we see that its derivative is

d/dxln(f(x))=1/f(x)*f'(x)

So here,

dy/dx=d/dxln(1-x^2)=1/(1-x^2)[d/dx(1-x^2)]=(-2x)/(1-x^2)

If you want, you can simplify the negative/minus signs:

dy/dx=(2x)/(x^2-1)