How do you solve $8 (1 + 2 v) + 8 = - 112$ $8( 1+ 2v ) + 8= - 112$ ?

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Answer 1 · 2018-05-25T03:16:46

$v = - 8$ $v = -8$

Isolate your variable to find the value.

$8 (1 + 2 v) + 8 = - 112$ $8(1 + 2v) + 8 = -112$

$8 (1 + 2 v) = - 120$ $8(1 + 2v) = -120$

$1 + 2 v = - 15$ $1 + 2v = -15$

$2 v = - 16$ $2v = -16$

$v = - 8$ $v = -8$

Check: $8 (1 + 2 \cdot - 8) + 8 = - 112$ $8(1 + 2 * -8) + 8 = -112$

$8 \cdot - 15 + 8 = - 112$ $8 * -15 + 8 = -112$

$- 120 + 8 = - 112$ $-120 + 8 = -112$

$- 112 = - 112$ $-112 = -112$

How do you solve 8(1+2v)+8=−1128( 1+ 2v ) + 8= - 112?