How do you find the rectangular form of $(4, -pi/2)$ ?

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Answer 1 · 2018-05-25T04:28:06

$(0, -4)$

Polar coordinates are represented as:

$(r, theta)$

Since we're given:

$(4, -pi/2)$

$4$ is $r$ and $-pi/2$ is $theta$

Use the formula:

$(rcostheta, rsintheta)$

The rest is plugging and solving:

$rcostheta$
$4cos(-pi/2)$
$4(0)$ $color(blue)(" The "cos " value of "-pi/2" is 0")$
$0$
$x=0$

$rsintheta$
$4sin(-pi/2)$
$4(-1)$ $color(blue)(" The "sin " value of "-pi/2" is -1")$
$-4$
$y=-4$

$color(red)((0, -4)$

How do you find the rectangular form of (4, -pi/2)(4, -pi/2)?