How do you solve $2 (r - 2) = 16$ $2( r - 2) = 16$ ?

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How do you solve $2 (r - 2) = 16$ $2( r - 2) = 16$ ?

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Answer 1 · 2018-05-26T07:35:51

$r = 10$ $r = 10$

Explanation:

Re-arrange and solve, make $r$ $r$ the subject.

$r - 2 = \frac{16}{2}, r = 8 + 2, r = 10$ $r-2 = 16/2, r = 8+2, r=10$

Answer 2 · 2018-05-26T07:39:05

$r = 10$ $r = 10$

Explanation:

As explained below:

Step 1: Open the brackets

$2 (r - 2) = 16$ $2(r-2) = 16$

$(2 \times r) - (2 \times 2) = 16$ $(2xxr) - (2xx2) = 16$

$2 r - 4 = 16$ $2r - 4 = 16$

Step 2: Add 4 both sides

$2 r - 4 + 4 = 16 + 4$ $2r - 4 + 4 = 16 + 4$

$2 r = 20$ $2r = 20$

$r = \frac{20}{2}$ $r = 20/2$

$r = 10$ $r = 10$

Checking the answer:

$2 (r - 2) = 16$ $2(r-2) = 16$
$2 (10 - 2) = 16$ $2(10-2) = 16$
$2 (8) = 16$ $2(8) = 16$

Answer 3 · 2018-05-26T07:40:28

$r = 10$ $r=10$

Explanation:

Solve:

$2 (r - 2) = 16$ $2(r-2)=16$

Expand.

$2 r - 4 = 16$ $2r-4=16$

Add $4$ $4$ to both sides.

$2 r = 16 + 4$ $2r=16+4$

$2 r = 20$ $2r=20$

Divide both sides by $2$ $2$ .

$r = \frac{20}{2}$ $r=20/2$

$r = 10$ $r=10$

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How do you solve $2 (r - 2) = 16$ $2( r - 2) = 16$ ?

3 Answers

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