How do you solve #2( r - 2) = 16#?

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Answer 1 · 2018-05-26T07:35:51

#r = 10#

Re-arrange and solve, make #r# the subject.

#r-2 = 16/2, r = 8+2, r=10#

Answer 2 · 2018-05-26T07:39:05

#r = 10#

As explained below:

Step 1: Open the brackets

#2(r-2) = 16#

#(2xxr) - (2xx2) = 16#

#2r - 4 = 16#

Step 2: Add 4 both sides

#2r - 4 + 4 = 16 + 4#

#2r = 20#

#r = 20/2#

#r = 10#

Checking the answer:

#2(r-2) = 16#
#2(10-2) = 16#
#2(8) = 16#

Answer 3 · 2018-05-26T07:40:28

#r=10#

Solve:

#2(r-2)=16#

Expand.

#2r-4=16#

Add #4# to both sides.

#2r=16+4#

#2r=20#

Divide both sides by #2#.

#r=20/2#

#r=10#