How do you solve #2x + 21= 4x + 5#?

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Answer 1 · 2018-05-26T16:12:30

#8#

#2x+21=4x+5#
is given:
substracting
#2x#:
#21=2x+5#
subtracting #5#
#16=2x#
dividing by #2#
getting
#x=8#

Answer 2 · 2018-05-26T16:12:37

#x = 8#

As per the question, we have

#2x + 21 = 4x + 5#

#:. cancel(2x) cancel(- 2x) + 21 - 5 = 4x - 2x + cancel5 cancel- 5# ... [Subtracting #2x# and #5# from both sides]

#:. 16 = 2x#

#:. x = 16/2#

#:. x = 8#

Hence, the answer.