How do you multiply and simplify $\frac { a + 9} { a ^ { 2} + 2a - 63} \cdot \frac { a - 7} { 8}$ ?

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Answer 1 · 2018-05-29T07:41:17

$1/8$

factorise teh denominator

$(a+9)/(a^2+2a-63)*(a-7)/8$

$=(a+9)/((a+9)cancel((a-7)))*cancel((a-7))/8$

$=cancel(a+9)/cancel(a+9)*1/8$

$=1/8$

How do you multiply and simplify \frac { a + 9} { a ^ { 2} + 2a - 63} \cdot \frac { a - 7} { 8}\frac { a + 9} { a ^ { 2} + 2a - 63} \cdot \frac { a - 7} { 8}?