How do you solve the inequality #3 - 2x > 7#?

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Answer 1 · 2018-05-29T09:56:21

#x<-2#

#3-2x>7#

Subtract 3 from both sides
#-2x>4#

Divide by 2
#-x>2#

Multiply by -1
#x<-2#

Answer 2 · 2018-05-29T09:57:31

Transpose terms

#3-7>2x#

#-4>2x#

Divide by 2 both sides

#-2>x# or if you want #x< -2#

The solution are all number smaller than -2

In interval form #(-oo,-2)# (excluded -2 because simbol is "<" estrictly)