Question

How do you simplify `sqrt48+sqrt147`?

Answer 1

See a solution process below:

Explanation:

First, we can rewrite the terms under the radicals as:

`sqrt(16 * 3) + sqrt(49 * 3)`

Now, we can use this rule of exponents to do the simplification:

`sqrt(color(red)(a) * color(blue)(b)) = sqrt(color(red)(a)) * sqrt(color(blue)(b))`

`(sqrt(16) * sqrt(3)) + (sqrt(49) * sqrt(3)) =>`

`4sqrt(3) + 7sqrt(3) =>`

`(4 + 7)sqrt(3) =>`

`11sqrt(3)`

Answer 2

`11sqrt3`

Explanation:

`sqrt48 +sqrt147`

`sqrt16*sqrt3 +sqrt49*sqrt3`

`4sqrt3 +7sqrt3`

`11sqrt3`

`----------------`

You must find first number which should be a square number.

Like `16` and `49` are square numbers.

Answer 3

`11sqrt3`

Explanation:

`sqrt48+sqrt147`

`sqrt(2*2*2*2*3)+sqrt(3*7*7)`

`sqrt(2^2*2^2*3)+sqrt(3*7^2)`

`2*2*sqrt(3)+7*sqrt(3)`

`4sqrt(3)+7sqrt(3)`

`11sqrt3`