How do you simplify $(c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}$ ?

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Answer 1 · 2018-05-30T01:06:25

$=>c^(63)$

$(c^7)^9(c^0)^5$

Anything to the power of $0$ is equal to $1$ .

$=(c^7)^9(1)^5$

$1$ to any power is just $1$ .

$=(c^7)^9(1)$

$=(c^7)^9$

When a power is raised to another power, the powers can be multiplied to simplify:

$=c^(7*9)$

$=c^(63)$

How do you simplify (c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}(c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}?