How do you simplify ${(c^{7})}^{9} {(c^{0})}^{5}$ $(c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}$ ?

Question

1153 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-30T01:06:25

$\Rightarrow c^{63}$ $=>c^(63)$

${(c^{7})}^{9} {(c^{0})}^{5}$ $(c^7)^9(c^0)^5$

Anything to the power of $0$ $0$ is equal to $1$ $1$ .

$= {(c^{7})}^{9} {(1)}^{5}$ $=(c^7)^9(1)^5$

$1$ $1$ to any power is just $1$ $1$ .

$= {(c^{7})}^{9} (1)$ $=(c^7)^9(1)$

$= {(c^{7})}^{9}$ $=(c^7)^9$

When a power is raised to another power, the powers can be multiplied to simplify:

$= c^{7 \cdot 9}$ $=c^(7*9)$

$= c^{63}$ $=c^(63)$

How do you simplify (c7)9(c0)5(c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}?