How do you simplify #(c ^ { 7} ) ^ { 9} ( c ^ { 0} ) ^ { 5}#?

Question

1031 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-30T01:06:25

#=>c^(63)#

#(c^7)^9(c^0)^5#

Anything to the power of #0# is equal to #1#.

#=(c^7)^9(1)^5#

#1# to any power is just #1#.

#=(c^7)^9(1)#

#=(c^7)^9#

When a power is raised to another power, the powers can be multiplied to simplify:

#=c^(7*9)#

#=c^(63)#