Integration of 2sinx??

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Answer 1 · 2018-05-30T11:25:09

$=>C-2cos(x)$

$int 2 sin(x) dx$

The constant can be brought out

$=2 int sin(x) dx$

This is a standard integral form. Sine integrates to negative cosine.

$=2(-cos(x))+C$

$=C-2cos(x)$

where $C$ is an arbitrary integration constant from the indefinite integration.