Integration of 2sinx??

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Answer 1 · 2018-05-30T11:25:09

$\Rightarrow C - 2 cos (x)$ $=>C-2cos(x)$

$\int 2 sin (x) d x$ $int 2 sin(x) dx$

The constant can be brought out

$= 2 \int sin (x) d x$ $=2 int sin(x) dx$

This is a standard integral form. Sine integrates to negative cosine.

$= 2 (- cos (x)) + C$ $=2(-cos(x))+C$

$= C - 2 cos (x)$ $=C-2cos(x)$

where $C$ $C$ is an arbitrary integration constant from the indefinite integration.