How do you solve the system of equations 5x+3y=10 and 3x+5y=6?

1 Answer
May 30, 2018

y=0 and x=2

Explanation:

5x+3y=10
3x+5y=6

Let us eliminate x first so we can solve for y. To do this, multiply the top equation by 3 and bottom equation by 5:

15x+9y=30
15x+25y=30

Subtract equations away from each other:

0+(16y)=0
16y=0
y=016
y=0

Substitute value of y back into one of the original equations:

5x+3y=10
5x+3(0)=10
5x=10
x=105
x=2

Double check solutions by plugging in the values of x=2 and y=0 into the original equations to see whether you get 10 and 6.