How do you solve the system of equations #5x+3y=-10# and #3x+5y=-6#?

1 Answer
May 30, 2018

#y=0# and #x=-2#

Explanation:

#5x+3y=-10#
#3x+5y=-6#

Let us eliminate #x# first so we can solve for #y#. To do this, multiply the top equation by #3# and bottom equation by #5#:

#15x+9y=-30#
#15x+25y=-30#

Subtract equations away from each other:

#0+(-16y)=0#
#-16y=0#
#y=0/-16#
#y=0#

Substitute value of #y# back into one of the original equations:

#5x+3y=-10#
#5x+3(0)=-10#
#5x=-10#
#x=-10/5#
#x=-2#

Double check solutions by plugging in the values of #x=-2# and #y=0# into the original equations to see whether you get #-10# and #-6#.