Question

Enter the equation of the circle described below? Center (-1, 4), radius = √3

Answer 1

`(x+1)^2+(y-4)^2=3`

Explanation:

The equation of a circle based on the center of a circle, `(h,k)`, and its radius, `r`, is `(x-h)^2+(y-k)^2=r^2`.

The given center here is `(-1,4)` and the given radius is `sqrt(3)`.
So, if we plug those in, we get `(x-(-1))^2+(y-4)^2=sqrt(3)^2`.

Simplified, it becomes `(x+1)^2+(y-4)^2=3`.