How do you solve e^ { 3c - 2} = b?
1 Answer
May 31, 2018
Take the natural logarithm of both sides:
ln(e^(3c- 2)) = lnb
(3c- 2)ln e = lnb
3c - 2 = lnb
c= 1/3(lnb + 2)
Hopefully this helps!
