How do you find a standard form equation for the line with (-2, 1) and (2, 1)?
1 Answer
May 31, 2018
y=1y=1
Explanation:
Given -
(-2, 1); (2, 1)(−2,1);(2,1)
x_1=-2x1=−2
y_1=1y1=1
x_2=2x2=2
y_2=1y2=1
(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)(y−y1)=y2−y1x2−x1(x−x1)
(y-1)=(1-1)/(2-(-2))(x-(-2))(y−1)=1−12−(−2)(x−(−2))
y-1=0/(2+2)(x+2)y−1=02+2(x+2)
y-1=0/4(x+2)y−1=04(x+2)
y-1=0y−1=0
y=1y=1