Hybridisation of XEF4?

1 Answer
zhirou
May 31, 2018

#Xe# is #d^2sp^3# hybridised, and #F# is #sp^3# hybridised.

Explanation:

This is the Lewis structure of #XeF_4#:

Quora

The steric number, or the number of atoms and lone pairs, of #Xe# is #6#. This means that it has a hybridisation of #d^2sp^3#.

The steric numbers of #F# are all #4#. This means that fluorine is #sp^3# hybridised.

Related questions
Impact of this question
6731 views around the world
You can reuse this answer
Creative Commons License