How do you solve #4x-2>6x+8#?

1 Answer
May 31, 2018

#x<-5#

Explanation:

First, rearrange the inequality so that all of the #x#'s are on one side
#-2>6x-4x+8#
#-2>2x+8#

Then rearrange so that all of the numbers are on the other side
#-2-8>2x#
#-10>2x#

Now, divide both sides by to get x
#-10/2>(2x)/2#
#-5>x#

So, #x<-5# is the answer