How do you solve $4 x - 2 > 6 x + 8$ $4x-2>6x+8$ ?

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Answer 1 · 2018-05-31T11:29:57

$x < - 5$ $x<-5$

First, rearrange the inequality so that all of the $x$ $x$ 's are on one side
$- 2 > 6 x - 4 x + 8$ $-2>6x-4x+8$
$- 2 > 2 x + 8$ $-2>2x+8$

Then rearrange so that all of the numbers are on the other side
$- 2 - 8 > 2 x$ $-2-8>2x$
$- 10 > 2 x$ $-10>2x$

Now, divide both sides by to get x
$- \frac{10}{2} > \frac{2 x}{2}$ $-10/2>(2x)/2$
$- 5 > x$ $-5>x$

So, $x < - 5$ $x<-5$ is the answer

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