√4+√9 square ?

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Answer 1 · 2018-05-31T14:20:58

$25$ $25$

As per the question, we have

${(\sqrt{4} + \sqrt{9})}^{2} = ?$ $(sqrt4 + sqrt9)^2 = ?$

Expanding this equation, using the identity ${(a + b)}^{2} = a^{2} + b^{2} + 2 a b$ $(a+b)^2 = a^2 + b^2 +2ab$

$= {(\sqrt{4})}^{2} + {(\sqrt{9})}^{2} + 2 (\sqrt{4}) (\sqrt{9})$ $= (sqrt4)^2 + (sqrt9)^2 + 2(sqrt4)(sqrt9)$

$= 4 + 9 + 2 (\sqrt{4 \cdot 9})$ $= 4 + 9 +2(sqrt(4*9))$

$= 13 + 2 (\sqrt{36})$ $= 13 + 2(sqrt36)$

$= 13 + 2 (6)$ $= 13 + 2(6)$

$= 13 + 12$ $= 13 + 12$

#= 25

Hence, the answer.