How do you solve $8 x + 3 - 10 x = - 2 (x - 2) + 3$ $8x + 3- 10x = - 2( x - 2) + 3$ ?

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How do you solve $8 x + 3 - 10 x = - 2 (x - 2) + 3$ $8x + 3- 10x = - 2( x - 2) + 3$ ?

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Answer 1 · 2018-06-01T06:33:22

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Explanation:

Given -

$8 x + 3 - 10 x = - 2 (x - 2) + 3$ $8x+3-10x=-2(x-2)+3$

$8 x + 3 - 10 x = - 2 x + 4 + 3$ $8x+3-10x=-2x+4+3$

$- 2 x + 3 = - 2 x + 7$ $-2x+3=-2x+7$

$- 2 x + 3 + 2 x = - 2 x + 7 + 2 x$ $-2x+3+2x=-2x+7+2x$

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How do you solve $8 x + 3 - 10 x = - 2 (x - 2) + 3$ $8x + 3- 10x = - 2( x - 2) + 3$ ?

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How do you solve 8x+3−10x=−2(x−2)+38x + 3- 10x = - 2( x - 2) + 3?

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How do you solve $8 x + 3 - 10 x = - 2 (x - 2) + 3$ $8x + 3- 10x = - 2( x - 2) + 3$ ?