In a right triangle ABC with angle A equal to 90o, find angle B and C so that sin(B) = cos(B). ?

1 Answer

B and C measures #90^@#

Explanation:

Let,
b be the length of the side opposite of the angle B
c the length of the side opposite of the angle C
h the length of the hypotenuse.

sin(B) = #b/h# and cos(B) =#c/h#

sin(B) = cos(B) means #b/h=c/h#

By cross multiplication,

#b=c#

This gives that the triangle is isosceles so,

B and C angle is equal to #45 ^@#