How many moles of $N a^{+}$ $Na^+$ ions are in 150 mL of a 0.200 M $N a_{3} P O_{4}$ $Na_3PO_4$ solution?

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Answer 1 · 2018-06-02T22:52:15

$0.09 mol$ $"0.09 mol"$

Moles of ${Na}_{3} {PO}_{4}$ $"Na"_3"PO"_4$ in the solution is

$"n" =\ "Molarity × Volume"$

$color(white)("n") =\ "0.200 M × 0.150 L"$

$color(white)("n") =\ "0.03 mol"$

There are $3$ atoms in each molecule of $"Na"_3"PO"_4$ .

So, Moles of $"Na"^+$ ions $"= 3 × 0.03 mol = 0.09 mol"$

How many moles of Na^+Na+Na^+ ions are in 150 mL of a 0.200 M Na_3PO_4Na3PO4Na_3PO_4 solution?