What is the answer for volume used by 9.6g of SO2 gas at a pressure of 830 Pa and at a temperature of 327°C?

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Answer 1 · 2018-06-02T23:01:53

$901.5\ "L"$

Molar mass of $"SO"_2 = 64\ "g/mol"$

Moles of $"SO"_2 = "9.6 g"/"64 g/mol" = "0.15 mol"$

From ideal gas equation

$"PV = nRT"$

$"V" = "nRT"/"P"$

$color(white)("V") = "0.15 mol × 8.314 L kPa / (mol K) × 600 K"/"0.830 kPa"$

$color(white)("V") = 901.5\ "L"$