Please can anyone help? We're doing simultaneous equations ad I'm a bit confused on how to get the second equation, I got 4s - 14 = 3s.

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Answer 1 · 2018-06-03T03:07:27

Let "C" be the original number of Sweets Charlie has and A be the original number of sweets that Anna has:

Charlie has 4 times as many sweets as Anna thus:
Equation 1: $C = 4 \cdot A$ $C = 4 * A$

Charlie eats 14 sweets, Anna eats 2 sweets
$C \to C - 14$ $C -> C - 14$ and $A \to A - 2$ $A-> A-2$

and after the change, Charlie has 3 times as many sweets as Anna thus:
Equation 2: $C - 14 = 3 \cdot (A - 2) = 3 A - 6$ $C - 14 = 3 * (A-2) = 3A-6$

$E q .1 - E q .2 = C - (C - 14) = 4 A - (3 A - 6)$ $Eq.1 - Eq.2 = C - (C-14) = 4A -(3A - 6)$
$14 = A + 6$ $14 = A + 6$

$A = 8, A - 2 = 6$ $A = 8, A-2 = 6$
$C = 3 \cdot 6 = 18$ $C = 3*6 = 18$

Thus, Charlie now has 18 sweets and Anna now has 6 sweets.