Need help with solving 4x-y=9, x-3y=16? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Karasuma · Stefan V. Jun 3, 2018 #x# is equal to #1# and #y# is equal to #-5#. Explanation: #{(4x-y=9), (x-3y=16) :}# Do #4x-y=9 # #(x-3y)xx4=16xx4# So #{(4x-y=9), (4x-12y=64) :}# Subtract the two equations #0x+11y= -55# #11y=-55# #y=-5# Replace #y# in the first equation #4x-y=9# #4x-(-5)=9# #4x+5=9# #4x=4# #x=1# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 4540 views around the world You can reuse this answer Creative Commons License