Question

How do you solve `7x - ( x - 3) = 3( x + 10)`?

Answer 1

x=9

Explanation:

`7x-(x-3)=3(x+10)`

First, multiply the brackets
`7x-(x-3)=3x+30`

Calculate the "`7x`" side
`7x-x+3=3x+30`
`6x+3=3x+30`

Take away the `3` from both sides
`6x=3x+27`

Take away the `3x` from both sides
`3x=27`

Divide both sides by `3`
`x=27/3`
`x=9`

Answer 2

`x=9`

Explanation:

`"distribute brackets on both sides of the equation"`

`7x-x+3=3x+30`

`6x+3=3x+30`

`"subtract "3x" from both sides"`

`6x-3x+3=30`

`3x+3=30`

`"subtract 3 from both sides"`

`3x=30-3=27`

`"divide both sides by 3"`

`rArrx=27/3=9`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=63-(9-3)=63-6=57`

`"right "=3(9+10)=3xx19=57`

`x=9" is the solution"`

Answer 3

`x=9`

Explanation:

We can distribute the parenthesis on the left and right to get

`7x-x+3=3x+30`

Next, let's combine the left side variables to get

`6x+3=3x+30`

Next, let's subtract `3x` from both sides to get

`3x+3=30`

This is unconventional, but since all terms are divisible by `3`, we can divide both sides by `3` to get

`x+1=10`

Subtracting `1` from both sides gives us

`x=9`

Hope this helps!

Answer 4

`x=9`

Explanation:

`7x-(x-3)=3*(x+10)`

`6x+3=3*(x+10)`

`2x+1=x+10`

`x=9`