How do you write $32^{- \frac{3}{5}}$ $32^(-3/5)$ in radical form?

Question

How do you write $32^{- \frac{3}{5}}$ $32^(-3/5)$ in radical form?

2 Answers

Impact of this question

7057 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-04T08:56:29

Se explanation below

Explanation:

We define $a^{\frac{m}{n}} = \sqrt[n]{a^{m}}$ $a^(m/n)=root(n)(a^m)$ .

By other hand, we know that $a^{- n} = \frac{1}{a^{n}}$ $a^(-n)=1/a^n$

With these rules in mind, in our case

$32^{- \frac{3}{5}} = \frac{1}{\sqrt[5]{32^{3}}} = \frac{1}{\sqrt[5]{{(2^{5})}^{3}}} = \frac{1}{\sqrt[5]{2^{15}}} = \frac{1}{\sqrt[5]{2^{5} \cdot 2^{5} \cdot 2^{5}}} = \frac{1}{8}$ $32^(-3/5)=1/(root(5)(32^3))=1/(root(5)((2^5)^3))=1/(root(5)(2^15))=1/root(5)(2^5·2^5·2^5)=1/8$

Answer 2 · 2018-06-04T15:47:13

$\frac{1}{8}$ $1/8$

Explanation:

$32^{- \frac{3}{5}}$ $32^(-3/5)$

$:.=(2^5)^(-3/5)$

$:.=2^(-15/5)$

$:.=2^-3$

$:.=m^-3=1/m^3$

$:.=1/2^3$

$:.=1/8$

Science

Math

Humanities

... and beyond

How do you write $32^{- \frac{3}{5}}$ $32^(-3/5)$ in radical form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write 32^(-3/5)32−3532^(-3/5) in radical form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you write $32^{- \frac{3}{5}}$ $32^(-3/5)$ in radical form?