How do you solve #3/7 = (n+2)/(n+12)#?

Question

↳Redirected from "Can you write a balanced nuclear equation for the alpha decay of Ra-226?"

1743 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-04T13:09:20

By arranging the equation, #n=5.5#

#3/7 = (n+2)/(n+12)#

#3(n+12) = 7(n+2)#

#3n + 36 = 7n +14#

#36-14 = 7n-3n#

#22 = 4n#

#22/4 = n#

#11/2=n#

Or #n=5.5#