How do you solve $\frac{3}{7} = \frac{n + 2}{n + 12}$ $3/7 = (n+2)/(n+12)$ ?

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Answer 1 · 2018-06-04T13:09:20

By arranging the equation, $n = 5.5$ $n=5.5$

$\frac{3}{7} = \frac{n + 2}{n + 12}$ $3/7 = (n+2)/(n+12)$

$3 (n + 12) = 7 (n + 2)$ $3(n+12) = 7(n+2)$

$3 n + 36 = 7 n + 14$ $3n + 36 = 7n +14$

$36 - 14 = 7 n - 3 n$ $36-14 = 7n-3n$

$22 = 4 n$ $22 = 4n$

$\frac{22}{4} = n$ $22/4 = n$

$\frac{11}{2} = n$ $11/2=n$

Or $n = 5.5$ $n=5.5$

How do you solve 37=n+2n+123/7 = (n+2)/(n+12)?