If you have lamp with 300 W power output And the average wavelength of the source is 590nm how many photons are emitted per second?

1 Answer
Jun 4, 2018

8.9 × 10^20 photons

Explanation:

Let the number of photons emitted in one second be "n".

"Power" = "Energy"/"Time"

"P" = ("nhc"/λ)/"t" = "nhc"/"λt"

Rearrange the above equation

"n" = "Ptλ"/"hc"

color(white)("n") = ("300 Watt × 1 s" × 590 × 10^-9\ "m")/(6.626 × 10^-34\ "J s" × 3 × 10^8\ "m/s")

color(white)("n") = 8.9 × 10^20