How do you evaluate the function # f(x)=x^3# for f(2)?

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Answer 1 · 2018-06-05T00:04:57

Plug in #x=2# into the equation so it is #2^3 = 8#.

If

#f(x)= x^3#

then

#f(2) = 2^3" "# [here # x=2#]

Answer 2 · 2018-06-05T00:05:49

#8#

Plug in #2# for #x#:

#f(2)=2^3#

#f(2)=2*2*2#

#f(2)=8#